(4x^2+1x-3)/(4x^2+9x-9)

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Solution for (4x^2+1x-3)/(4x^2+9x-9) equation: 


D( x )

4*x^2+9*x-9 = 0

4*x^2+9*x-9 = 0

4*x^2+9*x-9 = 0

4*x^2+9*x-9 = 0

DELTA = 9^2-(-9*4*4)

DELTA = 225

DELTA > 0

x = (225^(1/2)-9)/(2*4) or x = (-225^(1/2)-9)/(2*4)

x = 3/4 or x = -3

x in (-oo:-3) U (-3:3/4) U (3/4:+oo)

(4*x^2+1*x-3)/(4*x^2+9*x-9) = 0

(4*x^2+x-3)/(4*x^2+9*x-9) = 0

4*x^2+x-3 = 0

4*x^2+x-3 = 0

DELTA = 1^2-(-3*4*4)

DELTA = 49

DELTA > 0

x = (49^(1/2)-1)/(2*4) or x = (-49^(1/2)-1)/(2*4)

x = 3/4 or x = -1

(x+1)*(x-3/4) = 0

4*x^2+9*x-9 = 0

4*x^2+9*x-9 = 0

DELTA = 9^2-(-9*4*4)

DELTA = 225

DELTA > 0

x = (225^(1/2)-9)/(2*4) or x = (-225^(1/2)-9)/(2*4)

x = 3/4 or x = -3

(x+3)*(x-3/4) = 0

((x+1)*(x-3/4))/((x+3)*(x-3/4)) = 0

( x+1 )

x+1 = 0 // - 1

x = -1

( x-3/4 )

x-3/4 = 0 // + 3/4

x = 3/4

x in { 3/4} 

x = -1

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